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 ; C) A! E' w/ T- q
一、百家樂常见的错误
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0 a$ x2 }: T' M9 R5 G1 O8 @* {3的搭配机率是1/8，如果见持续3个不异的搭配，例如BBPBBPBBP之后用3式缆反买BBP（即PPB），中一口的成功机率是否1/8x/1/8x1/8x1/8=1/4096答案是否认的。由于持续3个不异搭配已经实际呈现，等于4096个搭配之中有4096–8=4088个搭配不成能呈现，只剩低余下的8个搭配可以呈现，所以胜的机遇率仍旧是7/8。现详细列出他们以便利理解：
! v& P! j3 V" L% c$ r- L0 A, R# ]/ y6 }. l4 f- `( k
1、BBP，BBP，BBP，BBB" G5 C `* n; w9 M; O1 r9 y
2、BBP，BBP，BBP，BBP
# \+ ^5 e% e+ f+ w( v) A3、BBP，BBP，BBP，BPB4 m( v# h3 w/ r/ {2 f* W
4、BBP，BBP，BBP，BPP* p, Z* |$ f$ n* j, z7 L
5、BBP，BBP，BBP，PPP
8 o* P1 w* D, M6、BBP，BBP，BBP，PPB8 e4 s( j+ `* s0 P3 X$ o) b
7、BBP，BBP，BBP，PBP
% n5 h/ P9 C+ P+ Z8、BBP，BBP，BBP，PBB
1 b" g% n& P H( S6 Q) k- E3 ~+ ^& S7 c! U, A5 U! e+ Y O
所以无论是什么搭配，当它已经实际呈现，它的概率必定是1。已经实际呈现的BBPBBPBBP概率是1，用3式缆买反的整体胜率依然是7/8。
4 B# _" B7 y' b, F0 `+ j! E0 Y# C, A6 @7 r4 r; ^
二、2式缆赌N搭配的错误有一个很自然的想法，之前开了例如BBBPB，跟着反买它即PPPBP去赢1个码,机遇率是1/32，死穴是反复的BBBPB。" w. r, V+ M9 J/ C
- A* M7 T& P( v为了节流金钱，好自然想到如果输了1口或2口才追，一来可以增加取胜机遇，二来可以节流金钱，所以便发生“同买分歧，分歧买同”的心理和策略。例如:见BBBPB，再见B，可能会认为如果买了第一口已经输了，余下四口用4式缆博赢一口的机遇会大一些；又或者等已出了二口BB才用3式缆博赢一口的机遇会大一些。现实上，这个策略是按比例裁减了一些胜及负的搭配来换取低成本:只见B才下注，便会错过8个BXXXX及8个PXXXX的搭配；同样只见BB才下注，便会错过12个BBXXX及12个PPXXX的搭配；所以这个策略亦没有提高风险回报比率，它的取胜机率完全由运用的式缆来决议，即2式缆=3/43式缆=7/84式缆=15/16。! n" @* D6 R, G* C5 g
三、结论1 K- K, N- u8 e5 n+ N$ X* N3 C
/ `) C- \* Y. N: n9 x无论等任何模式下注，如，PP后买B（拐弯法）；PPBP后买P连；PPBPPPBP后买P不连完全没有影响50%定理。! F& y7 w# m, Z9 U" u/ H1 _
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