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[lastpost] => 1820252 #####给赌友们介绍一种百家樂策略##### 1753894081 我是你的谁
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数学的统计数字 数学统计在一万次的局牌中, 开庄(Banker)约有4581次; 开闲(Player)约有4458次; 开和约有(Tie)961次.
, p x2 p9 P. e. i- Z! f+ {2 l. [- S) p- i* e# ]
由此结果可以得知, 开庄次数只比开闲次数多123次. 因此可以得到以下结论: 开庄与开闲的机会几乎相同. 根据此结论可以应用于以下的致胜法则. 致胜法则一连续买闲不买庄, 以系统投注法, 变码法来调整投注金额. 应用实例连输5手注码变化分别是1 2 3 4 5, 以1 为基数输一手加1以此类推.
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连赢5手注码变化分别是6 5 4 3 2, 赢一手减1以此类推. L: D6 P' h9 L- K, X
9 d) c! C k4 B3 U6 }& {连输5手连赢5手的结局是净赚5手. 应用前提用此法的前提是你比须有足够的资金来运作, 每次赢满18手, 就必须从新用1为基码, ! @4 N/ F% x6 b
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开始新一轮的牌局. 致胜法则二 凡上一铺所出的牌最后派的一张是: 10, J, Q, K, A, 2, 3, 4今铺就买闲, 凡上一铺所出的牌最后派的一张是: 5, 6, 7, 8, 9, 今铺就闲,庄各压一元.以系统投注法, 变码法来调整投注金额. 应用实例连输5手注码变化分别是1 2 3 4 5, 以1 为基数输一手加1以此类推.
* c* r$ \0 c# k7 f' M( s) i( [. p" ?5 w0 A( I/ d" w! p
连赢5手注码变化分别是6 5 4 3 2, 赢一手减1以此类推. # Y, z; c4 q: w6 @' Z
0 g) z$ ?. o9 _1 Z: M3 z连输5手连赢5手的结局是净赚5手. 应用前提用此法的前题是你比须有足够的资金来运作, 每次赢满9手, 就必须从新用1为基码, 开始新一轮的牌局. # N1 e/ v c4 ?2 T V4 e0 O
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连输5手连赢5手的结局是净赚5手 貌似是不可能的 啊 |
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