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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。
! l; Y7 N6 G2 K# A0 r( U
( p0 u4 Q; i ?8 Y+ k* m" n. J 用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的）! r6 d, s& r( |; P: \4 I
7 V+ p& X3 x( ~" l& P0 q
第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）
' y$ S5 ~4 r8 c8 v6 S
' x f4 d7 c: y' [ 第二行：O X X O O OX O X （第二行开始出现洞）6 w1 ^1 c( s) }
7 t" J5 e) e. q! N2 H7 \
第三行：O X O X X6 ^5 ^& Q* P, x
. p; Z8 t2 R# G7 f# S- D3 F3 l+ L 第四行：O X X/ M Q" d+ z4 n3 M; z; V
3 z. [/ x% P7 }0 ]
第五行： X
N4 N5 @; ^# ~8 Y* t5 r6 U6 C
1 I/ y" e" [5 E: c+ [ 那么新写出来的大路是怎么样的呢？
4 f4 X/ p3 f) d( {+ g) W: A8 M$ ^) t+ H
记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。5 W7 j' h3 Z% B7 V! [/ h8 b3 v. _
8 c( g! l2 y6 M$ M9 X% x
如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）4 L1 G& A: D7 l; V- b9 P
( b1 _4 X* u. _* o- q3 s 第一行：OXXOXOXO OXOOX（第一行不再是单跳了）7 ^% }3 t( X Y) _( M
) Z1 g. P* G6 R D2 \/ m 第二行：OOXXXOOX XXXXX （第二行也是全满的）9 p+ h D' K6 E, ?
! ~6 V/ t% P1 S( m% _" Q
第三行：OX OX XO XOOX （第三行才出现洞）
& p9 N& M, O2 F" c. G4 k5 x
& ?; P, |( G5 \+ x. m- E 第四行：O XO O XXX # S" U5 t1 L- ~- m$ |2 N" O% H2 r
7 j0 R! `4 r9 h9 M, o 第五行： O# e# e% h& s* M* w E i% u' ]
; i) \( s; v5 n
通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。. j3 V5 k5 ~2 Y* Q
/ Y& E- r5 p9 A9 r, i. }
大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。
$ g% x4 V9 z! F# ~9 s' v: y# a% p. _3 l7 K( B4 U
通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。9 R! K' R! ?" A: `+ n* Q
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