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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。
" x, m6 b* s. |" }8 R3 m- q8 U8 z! h7 D
" F) q$ q8 V( }( D 用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的）9 y9 Q4 Z8 K# c) B
7 p3 I, G& K2 d; @3 O# f& i
第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）
6 @+ c& T9 F# [+ p/ g0 A w9 @* P% S- b1 T- A4 V& L! }" U
第二行：O X X O O OX O X （第二行开始出现洞）
1 X6 |1 H$ q. X( Z4 k0 ? o- b: p, p
: m. J6 s( Q( ]( y7 j- n 第三行：O X O X X
/ V' j7 k: [5 U" `0 b7 M- O: m1 z% E$ X* J
第四行：O X X/ o, @' B; E9 z! S
7 y& ^4 _3 d7 X j3 X, t) Q2 b 第五行： X9 m! O4 L6 x1 v( u) v- Y
" h# ^; b ~& L2 k6 W9 s
那么新写出来的大路是怎么样的呢？
5 v8 b* Y# i# A* p( D! `, K
& ]5 j/ N* x' z1 u 记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。; _# e" n: y- O7 D, T
7 Y+ h; B9 q# Y8 U. ?$ k 如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）7 Q# s# ~7 p- Z6 X6 g% ]7 K
6 V% z5 u! }1 Q9 v: u6 F
第一行：OXXOXOXO OXOOX（第一行不再是单跳了）
) b6 ~" z1 K: ^. W9 `& P4 O( d4 r3 {+ m' I+ Q
第二行：OOXXXOOX XXXXX （第二行也是全满的）6 a9 G$ {6 x" S' i' b0 h" ]6 O- _
. {7 l; M) X9 V+ a+ I: H" X4 Z1 A
第三行：OX OX XO XOOX （第三行才出现洞）/ j5 u0 `6 V1 T8 k/ \
, \. e' ~* e4 _! h E0 v7 S 第四行：O XO O XXX
9 z- n0 O0 {* _1 {! }) b4 P3 p' _* j6 w& m: L- `& n
第五行： O
4 ?% M! O. Q# \, H F, f+ k) @ I) v" E0 q8 o+ p. q, S- t
通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。
l5 S u, E$ X9 i6 Y( w1 o/ }/ ]
大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。5 A) O7 }+ @7 d: X2 `2 C2 c
5 y/ e4 J) u- Q 通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。# {( i7 R/ T3 N7 }( O9 L
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