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6 x" v) E6 P1 H( |# C一、百家樂常见的错误9 U2 R+ i& W/ o3 R) F T
% P c$ _, d, T/ W! ~3的搭配机率是1/8，如果见持续3个不异的搭配，例如BBPBBPBBP之后用3式缆反买BBP（即PPB），中一口的成功机率是否1/8x/1/8x1/8x1/8=1/4096答案是否认的。由于持续3个不异搭配已经实际呈现，等于4096个搭配之中有4096–8=4088个搭配不成能呈现，只剩低余下的8个搭配可以呈现，所以胜的机遇率仍旧是7/8。现详细列出他们以便利理解： l. |% u' @: h
# k e- X% v( _" a
1、BBP，BBP，BBP，BBB: h3 {) \9 a5 u9 G+ C& C% U
2、BBP，BBP，BBP，BBP
5 M$ N5 R. M$ } j: ~3、BBP，BBP，BBP，BPB s1 ?( F' d& \
4、BBP，BBP，BBP，BPP
3 @& t7 I% H4 {9 U8 R9 o$ f6 I5、BBP，BBP，BBP，PPP
+ k6 g) D( x7 D: G0 M- H0 q! ]3 Y7 e6、BBP，BBP，BBP，PPB3 Y% R, J; |! q" H9 p2 K: }# n
7、BBP，BBP，BBP，PBP# Q0 L, ^7 K8 j) P% i6 N6 R o# \/ S
8、BBP，BBP，BBP，PBB2 `8 m4 m6 o: Y+ { K: h! h1 H
. { h% s$ r# d9 L' ~- V5 R所以无论是什么搭配，当它已经实际呈现，它的概率必定是1。已经实际呈现的BBPBBPBBP概率是1，用3式缆买反的整体胜率依然是7/8。) Q9 E# R; Z: C7 h
. X& P, G/ y" P& N, P二、2式缆赌N搭配的错误有一个很自然的想法，之前开了例如BBBPB，跟着反买它即PPPBP去赢1个码,机遇率是1/32，死穴是反复的BBBPB。
8 D6 Z0 _$ o7 ^+ ?2 G1 R" V( x* N5 z `
为了节流金钱，好自然想到如果输了1口或2口才追，一来可以增加取胜机遇，二来可以节流金钱，所以便发生“同买分歧，分歧买同”的心理和策略。例如:见BBBPB，再见B，可能会认为如果买了第一口已经输了，余下四口用4式缆博赢一口的机遇会大一些；又或者等已出了二口BB才用3式缆博赢一口的机遇会大一些。现实上，这个策略是按比例裁减了一些胜及负的搭配来换取低成本:只见B才下注，便会错过8个BXXXX及8个PXXXX的搭配；同样只见BB才下注，便会错过12个BBXXX及12个PPXXX的搭配；所以这个策略亦没有提高风险回报比率，它的取胜机率完全由运用的式缆来决议，即2式缆=3/43式缆=7/84式缆=15/16。% }3 f( M2 t: r8 T& m
三、结论' K2 c, o) N- C/ P; J) C
3 a8 Y+ q, N v d/ `8 _8 ^
无论等任何模式下注，如，PP后买B（拐弯法）；PPBP后买P连；PPBPPPBP后买P不连完全没有影响50%定理。
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