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[打法交流] 百家乐珠路理论技巧(转)
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通过我几个月来对珠路理论的研究,5 R+ y* d$ ?  k6 I7 G/ O
. ^/ B* ~  |4 f/ r# Z( {
+ z* q9 `* N" R& c( h; B发现了一个有趣的现象,
, U0 r, r& J1 G; V每一条大路,
6 q2 m" w; [% N$ `+ C& f* r0 h按2珠路排列,有2种不同的路数1 _% l2 j  Y8 @" u) {# f. A5 J) z2 d* V7 G7 B
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z9 `& G  }$ H, y. p1 @
按4珠路排列,有4种不同的路数
7 k) _! {) P% ]按N珠路排列,有N种不同的路数。: n1 f3 R9 @  p% ]* C+ [7 ^  E' t* W. J! ~
什么意思呢,可能大家一时不清楚,
8 ]6 w6 W# }. y; q2 w% s7 c我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
0 ~- p( C2 L7 l" p* X7 l3 R. ^5 Y假设大路开这样的路:! z  ~0 G3 v. K' o5 A4 ]" }5 w# u
# Z+ ~" t* ~- L3 S12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h  [& h( d  e- ~" v
够极端了吧, |# ~# k0 f. {+ }: E" J+ i
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
1 J* [; F9 ?( I7 b如果我们去掉第一口,就会出现完全相反的结果:* c3 Y  ?3 l3 F* t8 J
21212121212121212121212121212121" ]7 W% Y( k( `9 }
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C* J5 A- o% t& l: s3 S) M) A" P5 s
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O( \! d/ \& B: P4 ~! n/ l8 B
所以每一条大路,! R6 V# q$ h. c; z% O
2 ~# n" ~" \* B# Y# A按2珠路排列,有2种不同的路数。
- \( R/ |7 B2 E/ E再举一个列子:: g6 O' M0 x1 k2 T- ~
大路:122122122122122122。。。
; Q, Q: ?6 |( F  s4 O. M9 ~. ^( w按三珠路排列:
9 j0 @. ?5 x: I2 H122,122,122,122,122,122。。。$ W' c  Y' {$ I- f# r
去掉第一口,变成:6 G2 V! \" L' c" k: d
1 ~; Z7 }5 C: g6 B  {* U. _4 o' `221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M) a  e( j, X% q' p
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
) S9 }0 X1 ~- U) i1 y, o9 O212,212,212,212,212,: y& l, B; I6 e- m. J# c) `
5 g2 `! N  z2 D& K0 P1 Z去掉3口,又返回122,122,122,了) s* K) T( u$ M5 Z" W' ?; I
所以每一条大路,& ?8 I" N* {; b+ G6 o; q
按3珠路排列,有3种不同的路数。
4 a& V) e4 I/ a, ~$ L同理:按N珠路排列,有N种不同的路数。
" J% H# p4 [0 _/ W' a7 z( x我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
* l) X7 E9 Y: c0 h7 m6 p0 l) v字串83 L: R) G1 V- s2 Y+ Y- i  ~1 m: P2 z- M& Z; d5 u  q
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
: Z" d. B$ D3 @/ [1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |0 a$ A( \0 Q* f8 F
2、为三多理论提供了下注的多面性奠定基础。
& q1 Y  f; |/ Y) O* F9 N3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.# R0 N, |2 b/ o5 ^7 K7 i2 Q

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