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[打法交流] 百家乐珠路理论技巧(转)
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通过我几个月来对珠路理论的研究,5 R+ y* d$ ?  k6 I7 G/ O
  @/ b$ T+ ?4 z- M- H" J* M$ @6 J9 u* _- K
发现了一个有趣的现象,2 _1 }0 S# N- S: ]
每一条大路,, J$ P% Z: }0 n/ J3 G
按2珠路排列,有2种不同的路数1 _% l2 j  Y8 @" u) {# f' D# r; F8 d- u1 O/ n0 g# M
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
9 g& J& l; c, {. H按4珠路排列,有4种不同的路数% i  S) i; z4 e. t5 M/ Q) R
按N珠路排列,有N种不同的路数。: n1 f3 R9 @  p% ]* C: C( S' `2 p8 ~' |- O' d, f
什么意思呢,可能大家一时不清楚,
# i3 B. e5 i/ @# E0 d0 d  A我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
1 {" P6 E7 ^5 E) R* ^假设大路开这样的路:! z  ~0 G3 v. K' o5 A4 ]" }5 w# u
9 ^0 E& p& t  Y7 e12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h9 A/ d0 F6 A$ R4 \1 D
够极端了吧# H, Q. Y& n0 b6 L7 F
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
' B' v& a) q% z& y如果我们去掉第一口,就会出现完全相反的结果:# R2 m9 T, f% q- Q5 o" U
21212121212121212121212121212121
* k: W$ W# p) l" F7 n" U变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C0 X# s/ E4 P: f( }
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O0 {5 M% n( \; w; k. |
所以每一条大路,! R6 V# q$ h. c; z% O
- `6 A' k3 Z+ }% r3 C按2珠路排列,有2种不同的路数。
# S; k2 ^) T# V0 _1 C) J9 J9 X7 t再举一个列子:
/ A% {; i% U! V/ B' e大路:122122122122122122。。。
% r! e: c* n6 b# Z按三珠路排列:
. w- Q- A9 V: M" M. A122,122,122,122,122,122。。。5 n0 j% ]3 M7 L
去掉第一口,变成:6 G2 V! \" L' c" k: d& \* A5 y& S- Q- y0 e
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M# X7 P% \1 c$ x; k
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W2 K2 }( g2 M* }9 f9 \- @
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `: D" b$ y; Q, R5 ]+ B! P$ y* [- M! U
去掉3口,又返回122,122,122,了
' o' H, |: u2 S所以每一条大路,
5 l; a2 m) t! E# o5 V按3珠路排列,有3种不同的路数。
# Z3 @- f3 ]: H2 U- e. H$ t同理:按N珠路排列,有N种不同的路数。3 a8 H6 g6 [. K5 b# a( a
我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
: l# W5 l, C- C5 L8 O7 ~! T字串83 L: R) G1 V- s2 Y+ Y
, d9 R8 |; t* d# I* z! D- p, d3 [6 U. s5 J' [0 {1 A" m' k( @6 D" U5 \  P" G& Z4 c
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |& U! k" u( f1 Z. N& {% x
2、为三多理论提供了下注的多面性奠定基础。
. K2 ?, I. P2 S, ~3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路., L% X3 E0 }5 ~6 p

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