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[lastpost] => 2760735 【YZ】8月26日投注流水75095元 1756454320 rainwang
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。' s$ T2 z+ @: l# @/ [
, O& ~( T) A( a; \& i7 S6 e 假设大路开这样的路:
. D1 U. @* H& n! B T/ b3 C
* D9 T. S) x, [, M2 e5 o0 c 12121212121212121212121212121212。
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% t- N Q* R0 a! `: p* d( k9 ~ 按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:
' B) r* k4 _9 F! }) F' H9 B3 f( _/ k0 D( {6 @+ q# |
21212121212121212121212121212121。
$ }( n4 r4 G# U; c7 v
+ `, t/ d k1 e/ E' t: G( C- P$ m 变成了PBPBPBPBPB。1 ?3 x& g, a% Y0 X
* m. M: F/ l/ I7 n2 L 如果我们再去掉一口,又返回第一种情况了。, F% s; p2 n9 E) x5 G
4 z* U5 p, d: u0 i7 v. Q4 w 所以每一条大路,按2珠路排列,有2种不同的路数。
/ S. e' |7 s0 e6 i' ~. v9 d+ a2 F% ^! Q8 s1 P" ?
再举一个列子:, D/ Q& c+ R8 x4 ?& x9 I- k* X
* ~0 }) z! o" O( C6 ] 大路:122122122122122122。
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& ?/ {* w0 I3 l, H0 ]- F: n 按三珠路排列:' f# J5 Z! e, ^8 h
; H! V( _: n* {7 H( } 122,122,122,122,122,122。! \' b. v$ v, r7 S/ N6 Z
T) k( K: N: S6 g4 t7 v 去掉第一口,变成:( r0 h4 k j( t o
/ d* Y! v# d9 \/ B6 ` 221,221,221,221,221,去掉前2口,变成:0 p; o2 V0 |7 m% B+ l8 j3 u# s
7 H) E; Z P9 U" R( o! k8 _% v 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。% g' |% @) y' X
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同理:按N珠路排列,有N种不同的路数。
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我提出这个的意义在于:
/ V w- @) y4 [( w- A) \% B$ d! Z l0 C6 B5 M
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。3 U+ ]. k+ Y) u7 Z3 G- w6 S
# y {4 B5 l8 t) q 2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。' g+ @- o( `$ f1 R2 E/ }
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