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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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& i* J3 c8 H9 t" U% N 假设大路开这样的路:
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12121212121212121212121212121212。
# `4 B. f4 `3 n; c* ?( B0 g( k, {$ _# M+ j; b c y
按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:
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21212121212121212121212121212121。
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变成了PBPBPBPBPB。/ p6 F# j$ M& ?$ i8 L
+ p' _: T( R0 m Z3 o" @
如果我们再去掉一口,又返回第一种情况了。
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所以每一条大路,按2珠路排列,有2种不同的路数。 ~) W& X* B% o" P# ?
1 d! _' ^& P2 u 再举一个列子:6 P9 K* W8 g! }
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大路:122122122122122122。6 X: \7 A( x9 t* r, ], k, n
8 m4 A3 U, q: {) x( ?, B
按三珠路排列:: _& t3 F: \' ~$ C& L/ `
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122,122,122,122,122,122。6 s5 I. y$ |. h7 T# t" x( u% e% h
1 ~- @: K& m+ S5 J; |$ @; P) _ w 去掉第一口,变成:# j: @$ N: i: m) B2 m& l4 z1 J- S
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221,221,221,221,221,去掉前2口,变成:; f" c! {* _5 [. z; E
# @+ d* E. h5 [% M T/ ] 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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同理:按N珠路排列,有N种不同的路数。- P4 }: t* N) O" N
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我提出这个的意义在于:+ @# V1 G9 g- w2 @! X
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。. O$ h3 C3 Y; b# B
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2、为三多理论提供了下注的多面性奠定基础。4 {5 C c. v/ N6 j/ B2 l1 X' @% M
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。6 h* P/ i$ ^& _9 z, U9 ], q
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