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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。9 Q, J9 d* W$ ^. o# \3 _7 |* M
2 \! _( g8 |6 Z8 B) t5 u6 m
假设大路开这样的路:/ o1 Z, u+ o) C; D7 {8 S1 p+ H1 A
% V& {7 [. @6 I6 c4 S
12121212121212121212121212121212。
. n$ u0 {1 S$ \( d3 w9 \9 G, t# ?+ {
按2珠路,就是BPBPBPBPBP。
) {1 J! q4 m) u3 t
" a& H# V7 n3 J% v# w% w- S 如果我们去掉第一口,就会出现完全相反的结果:
; y0 h# q4 _- T, T$ V1 q5 E2 u7 p# O) r: B2 m$ g# u
21212121212121212121212121212121。
8 j+ U8 T9 e% K( g
" W7 H" r" X+ j3 P6 V2 B6 X! g# J 变成了PBPBPBPBPB。. ~' w/ a3 u6 V4 J# v8 S
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如果我们再去掉一口,又返回第一种情况了。& [+ A8 G" A2 E" }- _* L9 j3 T
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所以每一条大路,按2珠路排列,有2种不同的路数。 k* T1 I4 b6 k0 ^8 ?
# ?0 f! \% q/ j0 ~) I
再举一个列子:# n' q4 B) I: Z! L3 @
+ v3 F- y! _; G$ @* _( b 大路:122122122122122122。% j8 C2 _3 Q. {6 x) k( o
* E& B7 j) Q3 P/ `* u u
按三珠路排列:
% q n O/ U; Q0 b5 Z% W- v
5 g) H" i) Y1 E8 ^* M 122,122,122,122,122,122。
8 y7 }0 y- m6 }$ l& t$ }
$ J4 u# T8 F, O% p 去掉第一口,变成:- c4 R- A* Q8 ~+ n J" l
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221,221,221,221,221,去掉前2口,变成:
) v, J- E! @4 ]6 Q) g0 Y7 P& j
. ^2 \+ s* t7 }3 l 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。; Z* B1 J4 }/ M3 B, j" M- I+ y
+ b6 I3 @: _* Q Q! @+ e+ s 同理:按N珠路排列,有N种不同的路数。
9 g; A0 _3 p- w+ N
* _3 a7 t# l$ G5 M1 @+ ^ 我提出这个的意义在于:* j' h) X. s; Y
# c' V% j% k; ~" O5 [9 b 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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0 Z/ }# `7 q# b) e 2、为三多理论提供了下注的多面性奠定基础。* _- q) b. @* v4 O0 M
9 t+ |6 r+ y9 w: K# _2 u- H 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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