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9 [& C( m. q1 k  b/ g* i! N1 k) S2 }$ M9 R$ n2 L 
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。 
6 e6 d) \% i( g3 s; y7 w5 b 
/ N" S, Z( W  R8 K7 y: ^  假设大路开这样的路:' I4 |8 A$ P) S; [) F9 H( H 
 
: m  L0 y$ D7 ]7 Q* u  12121212121212121212121212121212。& t/ |3 c/ ^# X. @, V& ?; Q 
 
8 l/ d0 ^- c5 R4 A* I0 C  按2珠路,就是BPBPBPBPBP。& c( T' B" j4 d% `8 x5 u$ y; U0 H 
. Z+ c- O) y% |0 W$ S+ I  L 
  如果我们去掉第一口,就会出现完全相反的结果: 
1 E! ~- Q4 P* ~. l. g) z: e2 e( g$ r 
9 j2 n* M4 Q! t" [& f# U  21212121212121212121212121212121。4 [1 g) ~2 P0 ^4 B3 A 
 
1 u% z. v9 C$ Q  f& A% K# ]6 r  变成了PBPBPBPBPB。& l  k3 I( ]; {# a: s 
# p% ]' N' r9 T2 u 
  如果我们再去掉一口,又返回第一种情况了。+ ~. b8 L9 r# W' a: ` 
' `( q/ S0 {+ b 
  所以每一条大路,按2珠路排列,有2种不同的路数。- n) t6 ?# e( j  g+ X 
: u8 k- u" u* s6 [ 
  再举一个列子:0 z' m7 P; O/ m8 K2 [* Z& s3 X 
 
! V+ X7 m( y. ~0 W( y  H% E  大路:122122122122122122。" g4 h3 z9 J" p% j6 _- Q( z 
' t  s! B3 s8 r1 r 
  按三珠路排列: 
! V7 \: H+ C! s$ F/ _; W) C* b$ _5 z4 R- Q 
  122,122,122,122,122,122。# b! i% G% `- r; f0 ]7 k0 q 
 
* Q* U) R$ g* t. Z& D  g5 y  去掉第一口,变成:5 y, v7 {4 X- D: T 
 
+ E( ^+ O: z0 {0 M  p  221,221,221,221,221,去掉前2口,变成:; X0 g2 o, l' o3 ^' }0 l 
8 K. x- B7 ?2 d0 Q 
  212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。 
3 T( E: Y( S6 V$ z/ u7 M) y$ ?. n' s- Y( J! P* g 
  同理:按N珠路排列,有N种不同的路数。0 U4 z, y3 F# F; A" R4 ~! ~ 
 
: H5 b, p6 o& m5 e) C- e  我提出这个的意义在于:# l* c* V2 _2 Z3 u; @& R- m 
 
' ~) ^/ F7 m. o  Q6 A4 x  1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。 
# l9 f5 d7 P! n& d3 }+ c8 G$ b0 H5 `; G5 X1 ~- |5 W; u 
  2、为三多理论提供了下注的多面性奠定基础。 
+ S6 @* z$ w& [& e; W( X  f5 p" V6 \+ x6 o 
  3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。- V+ n, l, v" V% U0 k! T; j 
 
- D% Y1 P2 G8 W5 F. h- U6 \ 
0 C1 ~" Q/ Y+ v' P+ [4 y 
' M6 F" r( F% y$ P$ ] |   
 
 
 
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