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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O8 h7 ]' ]8 L5 q$ C( @2 b" k6 B
; M2 K1 q7 X# x: F
发现了一个有趣的现象,
: a1 G4 b. l( D% R7 N& S每一条大路,0 m0 N# J* m5 K: X
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f, f3 ~) o# F, {
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
1 i( o; k) D' _; y+ K按4珠路排列,有4种不同的路数
, S: I' T t, i: z1 z按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C
1 N3 L8 P+ d( W4 z; U3 G什么意思呢,可能大家一时不清楚,6 j, B# U/ v8 n8 {4 k
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l9 k2 f' O7 ]8 y; _+ i4 w
假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u
( z* C# m. H1 g! g) ?7 X: \12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
# _1 N1 v& v1 B/ Z+ k, X6 D& @. y够极端了吧# O0 Q& v$ u; }7 K
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F& V+ y8 o2 T/ d3 k5 [* g
如果我们去掉第一口,就会出现完全相反的结果:
( x& ]7 w8 ]- @( ~7 v+ |! O21212121212121212121212121212121
+ E" w8 W4 c1 [$ N& f变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C8 F8 z' ~% w |3 U
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O+ J1 I2 L" }0 F4 A( E$ Q
所以每一条大路,! R6 V# q$ h. c; z% O
# g- U% w# x7 f1 W0 Q按2珠路排列,有2种不同的路数。# l. c- Z7 D0 y
再举一个列子:7 @6 B! L1 p; R J2 }% `& B) n
大路:122122122122122122。。。
: r! m# x' G9 _9 G4 H1 w3 d按三珠路排列:
3 s6 S6 i& D4 Y6 L8 T% l122,122,122,122,122,122。。。 d8 _# j( p& m
去掉第一口,变成:6 G2 V! \" L' c" k: d" r. [ x0 A( q( `# X% F6 Z
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M
+ T/ D7 K$ s: g1 t8 | d2 I去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W2 q9 _% K9 Z- K; m1 { J( | R' }
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `
5 n' M/ d8 O4 P9 {9 S( R去掉3口,又返回122,122,122,了6 n) S9 k( N4 M1 E: ^6 `! O+ g5 c
所以每一条大路,
; `! V3 C! B' K* w- L0 z" N1 y按3珠路排列,有3种不同的路数。: J, x! \$ c7 w/ \
同理:按N珠路排列,有N种不同的路数。
; C3 ^* Z% |6 J! B3 W- P我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O h# K" O9 K: |) Y) g) B
字串83 L: R) G1 V- s2 Y+ Y3 O- ] }& }& U# M; r! t
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @( w8 c. Q6 c% b
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |6 }( G9 Z2 L2 R. }* |2 S c2 ^
2、为三多理论提供了下注的多面性奠定基础。
4 h5 k! |) o( s& T; y4 ?3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
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