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s/ F4 Q6 x! ~% \% E6 j
: k/ z+ o: i0 T8 F( t( J通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
, U+ T. a% f; u) a) ^) k. s/ r* P5 F9 A* f0 z
假设大路开这样的路:
2 S2 {8 [( P" \' _( y2 M' b' H& l }& k" ^
12121212121212121212121212121212。
5 [- V/ A Y/ E- d1 O! w; {/ U, \- w5 }- p9 n8 m. c
按2珠路,就是BPBPBPBPBP。
$ [3 C/ B: Q8 @/ z9 O8 _+ H) Q
如果我们去掉第一口,就会出现完全相反的结果:1 L& z6 `7 e0 Z6 Y
4 |9 n# e( y v |6 }" T+ K
21212121212121212121212121212121。
- f' r A2 s9 ?* [/ t
) O P, \8 J' T4 i B# |* o6 E1 W 变成了PBPBPBPBPB。0 q- U3 z6 u7 L3 H& h* @: l; s: C
. _$ U; s, f8 ]$ J$ g8 i; {# q0 `
如果我们再去掉一口,又返回第一种情况了。' T4 T) J4 L9 B7 X
! Z9 X) q$ q5 ] 所以每一条大路,按2珠路排列,有2种不同的路数。5 s/ |6 ]! q; o5 L! H% q4 l
. J8 Y; ?) t& w* v8 B% ~
再举一个列子:
- t2 O6 e0 v) P+ P
- L4 V* b. r6 R [ 大路:122122122122122122。" f9 T3 A4 { T* Z1 E0 n( [$ U
2 ^/ ~8 d4 u0 {0 ]. `* R2 o 按三珠路排列:
( f `9 D d) M: c* G0 s$ B! W% ?; }; R3 G: |, M b. }. i. c
122,122,122,122,122,122。1 ]/ D5 m) J) a. ~& H% y6 ~
2 i5 u \& A/ I$ E" { 去掉第一口,变成:
9 G1 q0 k2 K1 z3 b5 K" C7 i, m, M# A: F( I& e
221,221,221,221,221,去掉前2口,变成:7 }* x e+ _. F
6 z/ M1 O5 c; ^$ ^ 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。; z* f2 u* U- @% @! @9 k) A* b
' w) T2 o$ _- r t9 M3 S 同理:按N珠路排列,有N种不同的路数。) H; V) G- u8 E8 P, b/ B' X& Z8 Q, v& B
/ _% o( s$ O b! U- N
我提出这个的意义在于:
! p6 v2 \' t9 T; i
( K9 H+ w5 ]- L. w8 K 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
+ P% S H' J) @+ y; L! G/ B, g* p
; M& c# ~9 v/ A! d$ Z 2、为三多理论提供了下注的多面性奠定基础。4 e6 N0 \4 [. ~- Z
0 H& w- [" g$ L8 ?9 E
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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3 K7 K: J w: b* C {
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