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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。+ g+ V% S& t! `6 @
3 g1 K. ]! [! M: A8 Z& }5 R5 h9 g 假设大路开这样的路:% o# C( B6 J. ] a* \6 Q
x7 V( [" `: { 12121212121212121212121212121212。: L$ g5 s* {9 A, S, _. L& F7 M$ S
( l4 x9 u. x# }* C# Z% a
按2珠路,就是BPBPBPBPBP。+ |5 H1 h& Z/ M* [
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如果我们去掉第一口,就会出现完全相反的结果:
8 g1 d. {) H; G) D7 X( d9 a# X, ?! [( Q- D# T# i- T
21212121212121212121212121212121。
* u% s+ _7 E' n: K7 a# S
! R- h6 c9 h2 T0 }* y& Z, F1 x 变成了PBPBPBPBPB。
$ P) J+ n2 L4 [$ w4 N# {) J& d/ |5 j' K
如果我们再去掉一口,又返回第一种情况了。, [4 J' D. g% M" C$ A. l& W
8 b( l! C: N6 T" Z1 X6 ~4 ~( a8 n 所以每一条大路,按2珠路排列,有2种不同的路数。: J+ S$ U: X$ ?0 E' c2 ]: R- r
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再举一个列子:) a' e6 f+ j6 X) w& E0 I7 E
# ~ _' H4 A- r/ C: [; a 大路:122122122122122122。- N+ u. N# K5 D$ ^! r m
$ \1 Z6 _' z* }& @ 按三珠路排列:% Z( k: E8 J8 ^% D
2 L. [. U$ v- R6 ]: c! u/ z 122,122,122,122,122,122。
4 i0 w8 A' @& J4 k* m5 A3 _, |: C2 b" y+ M% g6 n
去掉第一口,变成:
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221,221,221,221,221,去掉前2口,变成:
2 c o6 z& G9 _: F
6 V7 n! w2 |! g" R9 ] 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。% R4 Q7 ^2 \5 s. a: A0 g9 l; A
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同理:按N珠路排列,有N种不同的路数。6 G% D" \8 D- G7 v+ K# f
7 n3 d. U# B$ E4 p. k" T/ [+ B 我提出这个的意义在于:9 \& L; r) U& a4 Y( n7 y, |1 g
3 q/ j+ w4 A6 K% ]8 X 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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! \4 s& y7 ~7 ?! ~ 2、为三多理论提供了下注的多面性奠定基础。
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% N0 e' s# G* m$ g$ M( J2 J 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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