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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
. \$ b0 P+ G/ J3 P
^% b0 X+ `7 q* j1 I( e发现了一个有趣的现象，
* X# ]& ~$ j2 l: ?每一条大路，+ z* m* L7 J/ `; i2 O; A
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f& `4 t% C* E5 L
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z" D3 o. J9 |3 ^9 o
按4珠路排列，有4种不同的路数
. w ]2 W! O- U, l" n( F9 w& a按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
/ w2 }" M( ?& O" x! }什么意思呢，可能大家一时不清楚，
. X% u1 k' Q y$ U) J6 u2 Y' H8 s' }我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
/ z* O# F% i' j) e假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
6 s4 Q1 ]0 Y) X+ L; ]& P" o12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h8 F1 S% |$ S6 b
够极端了吧
/ U9 v+ `5 ]/ a, ^7 i按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F+ w2 w2 ^! h( ]0 p
如果我们去掉第一口，就会出现完全相反的结果：
9 b3 {) |+ R X9 h& R212121212121212121212121212121210 f" |" h) X, U/ g6 K6 @8 v X4 A% S
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C( D5 j# j6 L3 K* M6 c, M6 _
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O# }: @7 n2 k: {: ]: U; X4 A# V9 I+ C
所以每一条大路，! R6 V# q$ h. c; z% O
/ c, d/ f, l# J4 j5 o; C/ N按2珠路排列，有2种不同的路数。8 L8 L. j8 d& _: r& \2 k
再举一个列子：
+ H# ?! t/ w9 c! R7 e. W& K3 _4 @" N大路：122122122122122122。。。
1 B: F% I: I; {$ \6 `4 ]按三珠路排列：
& @4 I7 i3 d1 c4 w& s122，122，122，122，122，122。。。 T+ R2 ?. R u" P
去掉第一口，变成：6 G2 V! \" L' c" k: d
' C+ X" g$ o+ g221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M$ a% b4 v/ L5 D- Q: w% l+ @
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
8 o+ R8 m) Z8 Y3 W- x212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
8 v( j! v" P+ P去掉3口，又返回122，122，122，了+ \* o$ w7 B5 G* y+ r- w `
所以每一条大路，
' y: H7 n/ V" ]/ W0 W; K按3珠路排列，有3种不同的路数。
6 h* ?' ^, |+ g% D$ t: [, N _# H! Z同理：按N珠路排列，有N种不同的路数。
4 k1 ~+ N5 _% s我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
9 Q3 x: H* c }( \: x字串83 L: R) G1 V- s2 Y+ Y1 g- T% L. L& S6 |& P7 w; B$ I9 l8 I5 H
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
' i& A% H1 d% g( p4 |8 h) M1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
( |4 D; @, V. E8 R6 T2、为三多理论提供了下注的多面性奠定基础。# E$ Q9 N1 b, L$ e( q' z* `
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路., @; J! }$ X- U& l3 K5 k: M3 {
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