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h: x) t# [9 w& R! R通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。- H( U( V' U9 Z
5 _. J3 p. F3 H) m x 假设大路开这样的路:+ m* b3 @. l! x0 v1 }
" E, I0 Z2 t3 G! X 12121212121212121212121212121212。( ]: R5 W+ l$ W1 H1 h3 v
, w H" o1 A5 D% Q: O! i, T9 L
按2珠路,就是BPBPBPBPBP。/ g5 H3 o# E2 V. v! _/ `; Q
$ q2 R6 Y: E' z% p ?
如果我们去掉第一口,就会出现完全相反的结果:7 B5 o$ n2 ]/ _) A# i
# N% c ^, C3 r2 A
21212121212121212121212121212121。
* d6 G7 B' Q& E d3 n+ v$ z
3 v4 H; u# \4 N. D 变成了PBPBPBPBPB。' j1 b& _/ _( r4 N
+ n' ]6 t3 S5 o6 [7 {3 h
如果我们再去掉一口,又返回第一种情况了。
6 k7 ], i! t. M: m+ J- E c6 c
* R0 t8 d5 D! r) x 所以每一条大路,按2珠路排列,有2种不同的路数。
u' r2 @. {$ T2 D" A
/ @$ [; Q8 z4 m) g: j9 @ 再举一个列子:7 [" @8 t1 U+ O/ w
+ D* D2 v( `- B 大路:122122122122122122。6 \. I* f i9 x2 p, A! Y! i
5 z4 n8 X5 e0 e4 v; i4 h5 y6 s
按三珠路排列:$ I7 E# L' U% N
" P8 f$ r: J" M1 k e. Y+ m
122,122,122,122,122,122。* L$ N: g* S. s R1 P* ^4 H K; \9 j
8 [: i6 G% x4 s
去掉第一口,变成:
7 ?) H) S: g4 W/ E0 S; I x
) Y+ A; |" O k. Q5 o 221,221,221,221,221,去掉前2口,变成:3 ?2 S T; j( p" ~: X ~" L
* D5 `% T% P( F; a" E+ \2 e
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
2 [" d% `6 U8 m2 U8 y4 k$ M0 t* a0 d) ~0 d. X
同理:按N珠路排列,有N种不同的路数。
3 Z! n1 A) e, z1 f
3 t" A; M( u/ r3 {( X ~ 我提出这个的意义在于:
. s$ q4 o2 `5 d+ S6 ?) Y7 ~" g+ G3 P; ]
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。7 G8 C7 D/ ]$ h# p$ Q2 a
8 \& b- p9 l& ~) o" N+ i2 d 2、为三多理论提供了下注的多面性奠定基础。/ B3 I) C7 v" N; R
! Q j/ k7 y! I 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。% ?8 }; s# c0 O6 k6 C, R! D1 p2 Z
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