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% V3 B6 |7 B. W$ p d \( q9 j" K, l g# _3 f4 o6 C9 X7 O) \2 [9 R. q
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。) L3 F1 P$ {. V
5 f9 z1 v' q, a0 ?3 x
假设大路开这样的路:; i& x& t4 n4 y( h$ d" d/ P: L% \
% r% o& t% q u' a- j
12121212121212121212121212121212。. A, t5 m/ h. C/ E3 S
: E9 `' X6 S- W6 I0 z5 N1 Z
按2珠路,就是BPBPBPBPBP。
" ~: a( f2 q% A% P2 r
; C Z$ {) ~5 y% ^5 ?* x 如果我们去掉第一口,就会出现完全相反的结果:
5 I0 S9 a/ e0 v8 R
/ b. F4 r: X3 \- R 21212121212121212121212121212121。
6 |8 v3 B7 p/ W& Y
1 ] i6 R& w) g4 S$ {( U 变成了PBPBPBPBPB。5 M/ N( t J/ T* F: `2 G/ e# ]
2 i: B" O/ g' [5 T7 Y/ p+ M 如果我们再去掉一口,又返回第一种情况了。
& I4 _- F+ I1 e3 V/ B" v) h; Y4 c6 A* {) j6 H6 r* W; f. s
所以每一条大路,按2珠路排列,有2种不同的路数。
t/ z" j7 p8 F* r* N- Y) J9 O U+ m2 n) h" |6 l+ B5 \
再举一个列子:
/ E. [! a9 Z1 \/ C3 [; h- u
. B2 Z# U* x4 k0 {, a 大路:122122122122122122。9 c9 V; _+ }. m9 e. k3 ^0 s
3 x7 l: e5 Y2 O, v6 @
按三珠路排列:# c5 P2 S/ _' E" j2 N6 i4 S
, s: p* z: F6 |( n$ O- m; O 122,122,122,122,122,122。3 Q' J+ a: l- c5 _. d4 I
% E7 e- ` _8 a
去掉第一口,变成:3 R$ Z. R7 V! r# L5 i. W
& l; N- a! k b$ | Y
221,221,221,221,221,去掉前2口,变成:
2 G* Y y" u: i( Z' _8 x
' R- Z7 `) h) R4 C& M! H* g$ R* O 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。8 ~: q6 l) x! k- G: K( _/ W% | P( i
) r: O' h' A4 h' l$ H f4 K 同理:按N珠路排列,有N种不同的路数。* \# H: T% i* E9 Q" K
* R& G+ O5 m8 x f% s3 U4 D 我提出这个的意义在于:4 k3 X$ ?! J) A) U# F- z
- `% T# z- E& Q* {" e- ` 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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2、为三多理论提供了下注的多面性奠定基础。' L* X" G+ r4 z3 Y( g" ?4 ^
. a4 F" y1 B& [4 J# [# @, E 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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