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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O, L' }/ |- k9 C; P& h
8 W+ V3 y, T+ t) R9 f. L8 o发现了一个有趣的现象，
5 J6 G% W( n, S每一条大路，
# a. b( _3 e, N5 H$ ]! v0 {; W B按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
& {- D6 a# [ f* x按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
3 M' ~% r$ S2 d按4珠路排列，有4种不同的路数
5 G f# }/ M0 Z按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
, S% I* |$ ~# ~ S% P什么意思呢，可能大家一时不清楚，2 c1 k* k) [% D9 F4 l
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
7 b9 g7 C9 I0 X5 d4 O假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
' f1 O, `4 ?/ i1 O) J3 E7 k12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
8 G& d& y/ M/ m6 o, I& R% V够极端了吧
$ d% c) }% P* s0 r% E9 D按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
) O8 L% O$ m; x3 U) S如果我们去掉第一口，就会出现完全相反的结果：# A: A1 y2 e4 ]' { i9 A
212121212121212121212121212121215 `$ S, W- r/ y" s& q+ z( z
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C F5 C0 V# V! w8 k7 e& k' l+ t
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O2 W/ `' N& P8 l1 x' T
所以每一条大路，! R6 V# q$ h. c; z% O( [7 e' d. ^3 _5 ^9 F) K5 M5 H$ Y
按2珠路排列，有2种不同的路数。
8 i! F, h* Z, w4 ]% A再举一个列子：
" }* |6 o" C+ Y* u大路：122122122122122122。。。 }. ]" U% \4 h, I0 P
按三珠路排列：- p3 }/ P- P; [! B
122，122，122，122，122，122。。。
" b+ K$ b X1 |) o3 o去掉第一口，变成：6 G2 V! \" L' c" k: d
0 T* b% C5 r9 G- y/ U7 P221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M. p. L Q( E, I
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W1 a9 j2 N& k9 F2 |
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `* M2 V! G& j! r* O' A: X# ]
去掉3口，又返回122，122，122，了. t) k8 p7 g8 z! {
所以每一条大路，, x- e/ T O/ g8 [' c
按3珠路排列，有3种不同的路数。6 [$ i6 `) l& Z# D2 g+ t
同理：按N珠路排列，有N种不同的路数。
' v! Z) x) \3 L A9 | j( z2 S我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O5 E/ b: v9 l6 {5 _
字串83 L: R) G1 V- s2 Y+ Y
, x4 r1 K" Q. q G: K- p, d3 [6 U. s5 J' [0 {1 A" m' k( @8 s( G7 i1 I& Y$ l) _, Q
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |) ]) V# \# ?$ s4 c: A3 Q$ J
2、为三多理论提供了下注的多面性奠定基础。
( ]. U" H2 u6 {* w, Y3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.% {% c/ G3 i4 o; m F" U+ A
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