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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。- M- Q5 Z$ c3 d1 Y/ I: y8 U
N7 o; ?7 G. v0 k9 |, q5 f9 R+ D 假设大路开这样的路:, L$ L ?8 e- L+ l* n- b; Z
! h' d: S: {9 W$ \+ ]" J 12121212121212121212121212121212。
]9 x' u" s, ]+ C: v! {+ C6 J3 g$ [( ^8 b9 K- o5 e
按2珠路,就是BPBPBPBPBP。7 s- e# r2 `( G/ A l
% H7 V7 Y1 R" Q1 o, a9 e
如果我们去掉第一口,就会出现完全相反的结果:
* Q! T" H _1 I( b s
% h3 X) a, Z0 H 21212121212121212121212121212121。2 I: r! f0 ~9 v* n4 f
8 ~. K: C' J5 s$ \$ Y8 R! T# z2 S 变成了PBPBPBPBPB。
1 ^. a$ w% w6 l0 O8 R& O9 n
' |, m" F1 e0 W8 O9 Q 如果我们再去掉一口,又返回第一种情况了。8 \6 Q) D1 B' B) Z2 r/ X
, g' p4 m+ b, V6 y/ |. o
所以每一条大路,按2珠路排列,有2种不同的路数。6 a/ V: i+ a1 `/ G& a* |
+ F3 R7 B0 h- d( g4 E$ E
再举一个列子:
! P2 P' H+ u, a; N( c' p# e. N% e. S8 A0 O- n) G8 ?8 P
大路:122122122122122122。% A2 u' g3 H9 j/ z" \
0 n5 V5 J# e- a# P Y1 E0 [3 \
按三珠路排列:
8 X4 Z" m$ _6 T% k/ K+ s4 O* L2 J0 P% x3 d6 G; i1 a
122,122,122,122,122,122。0 W$ p5 |5 ~) s7 B
" B; b) ^2 h. \ P
去掉第一口,变成:/ P) A8 P5 u. f6 G, ^5 `
5 D2 P' }; q! g" c( P7 ~2 n7 h3 h
221,221,221,221,221,去掉前2口,变成:& ^5 d7 u+ @9 a3 X0 _5 s% F" |
- X3 U6 t+ C* h. q4 h3 l0 r 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。; Z2 P* B* m9 w" M( m% d
9 N' O: d+ Q( _0 J" K6 B 同理:按N珠路排列,有N种不同的路数。& q0 ]3 j; ^9 Y
) e% |- h; g; \& h 我提出这个的意义在于:: H4 L' v, r7 X3 l- M5 B
3 m# u: K: C1 p% [ 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
: b2 V+ q$ a- M) V7 m% x' c) f5 p* ]0 K1 o8 E3 L
2、为三多理论提供了下注的多面性奠定基础。
8 d N/ t+ e; S- p4 R e" a Q# Q* Q
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
" C+ z/ L2 D) N& K1 Q4 J& L! \) ~! p, Q1 g& \2 A- E( y
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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