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[lastpost] => 2763770 【YZ】9月8日投注流水7204元 1757399631 rainwang
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
8 m( o3 ?( I9 g r! R1 K
U9 ~0 h# k, b [ 假设大路开这样的路:, u, ~( z7 m4 U; ^7 {+ D5 X( J: [# T
# G: |3 L0 {4 A4 W! m1 X
12121212121212121212121212121212。
7 N8 W# d$ p' W% v& o
; ]. N5 T3 K% f2 t7 i! B2 O 按2珠路,就是BPBPBPBPBP。; t+ z8 Z( O5 f2 N1 z$ r
$ Y% m. J7 q' V 如果我们去掉第一口,就会出现完全相反的结果:. s, K0 ~: D& F; _6 H
+ O0 A( V6 P0 x* Y. E6 d1 Y2 f& Z 21212121212121212121212121212121。9 Q% Z! _; L/ c- H, u. @
# K ?) X0 J r6 c3 q) R# @
变成了PBPBPBPBPB。
9 W# f% d* a3 s5 Z
4 q0 F2 T( Q( o- B& y+ |' r4 Q 如果我们再去掉一口,又返回第一种情况了。
+ c+ ~5 q& c6 r$ C* K% F3 L6 N, j. |9 |3 W8 m4 j
所以每一条大路,按2珠路排列,有2种不同的路数。) X) {4 j; |) r0 [
9 U o9 `" x; q6 b$ P 再举一个列子:
4 { Y2 k2 }9 d9 G ~7 q7 n3 z
2 M( P1 Q6 D1 V/ v4 f" | 大路:122122122122122122。1 X5 L# ]9 _3 S- m O
- D0 u7 g ~0 n 按三珠路排列:
* g1 f$ W5 ^" a
4 A V' ?) t. _ 122,122,122,122,122,122。* R5 T1 w" X3 H* j! G, w b* j$ T% f3 p
/ n: B8 u) a" N; u) w
去掉第一口,变成:% h. e8 @+ q9 E: d2 y* ~
1 U, K6 v' `; R 221,221,221,221,221,去掉前2口,变成:1 M; U) C' K7 E, T: e7 k
3 Q5 \' ^2 r1 f# f' Y4 O( o+ F 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。# a6 O; y" b% }6 W' c2 I
9 Y2 L5 j0 B- U6 Y7 j. _
同理:按N珠路排列,有N种不同的路数。* L! |# _8 z# ?0 q# n7 z! {
9 F& l6 t! w! P- g 我提出这个的意义在于:
& U0 _( a/ R) [/ o8 R1 }/ V& i8 Q" ^' z
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。( P/ c0 y+ l( b& b: ^& b
" ]) [0 ^+ H' I; y
2、为三多理论提供了下注的多面性奠定基础。1 a* a- o% G- b& P; _
! O- [3 f& @4 V2 \; Q4 d
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
% p4 r8 S0 n& Q g3 t/ N" \; G( a+ M) S. B* \1 a
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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