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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。. v, w6 b' s* O( ^5 B- W
: P/ e% Z0 A# [# s% G5 a$ E5 v6 j( j# a 假设大路开这样的路:
2 i6 u# f4 O& @2 o3 w7 t: Z7 \1 N: \( Y1 E" t1 t6 J
12121212121212121212121212121212。, p- I; c! O' Z3 D1 i
' y- b/ e9 T5 M: M
按2珠路,就是BPBPBPBPBP。/ H+ `: ~' ~8 v( C
$ L- c+ v4 j- t. a
如果我们去掉第一口,就会出现完全相反的结果:
- \5 {( c- K0 m3 \) k" E: h; N* g% ]6 K* b
21212121212121212121212121212121。
" v( L+ {* G( A& f" P8 W }- l7 d$ f# @( D
变成了PBPBPBPBPB。
4 a2 v U" L* ]7 J& v0 X: d* P
" S$ r6 f' ~! {8 [' L9 L6 {7 l, @ 如果我们再去掉一口,又返回第一种情况了。
/ t& `9 W/ S1 v2 n5 R1 z# ]
* O- s( T K \& U- i 所以每一条大路,按2珠路排列,有2种不同的路数。
& d0 k7 s8 g% U
) j/ d; g7 A) U4 i8 \( ]. f 再举一个列子:
; q9 Z' y, ]! @! J, {1 V+ |/ T6 t/ m8 o" y( t
大路:122122122122122122。8 {) [6 y1 x' M+ H0 ^2 I2 p, F
' p8 L/ t/ ^$ x7 {( u# x) P
按三珠路排列:* D: C! f/ N# h
, i) e& S1 ?& M: |4 _: @
122,122,122,122,122,122。0 q( i6 L: J" ~; D, r, Q
, S& s6 Q) O6 M
去掉第一口,变成:
- u' E Y% ]$ n) N7 k0 O0 L+ @
221,221,221,221,221,去掉前2口,变成:/ L' N* ^- t% K, J. x3 H/ U
( x* n! y( ?* T( C- T3 J8 V 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。 X4 W1 |: O2 y' T7 H1 k, p
6 A6 ~7 o; M& l4 K& z
同理:按N珠路排列,有N种不同的路数。$ o% g6 B. \7 s3 V# s3 p
+ D& j( i y8 q4 b
我提出这个的意义在于:% w0 ?! t6 c0 c$ E( j, I5 T+ n
. K/ u. j) j& k6 M ]3 | 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
' v2 g! ^. G$ }2 v! x( l; K
) b8 a+ O# m3 F! u 2、为三多理论提供了下注的多面性奠定基础。
+ Y2 \ v$ A q1 f
/ P6 |7 d! U2 j/ n5 K 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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