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" D+ B  L5 Z  Y6 s: u& P7 B8 M9 v  M* y/ t7 }) E1 j. X' X 
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 Q6 W" W: I4 y7 ?+ @9 B2 j 
 
7 P% a  C/ U# e$ f# M  假设大路开这样的路: 
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  12121212121212121212121212121212。7 a6 W% |! A. z) I1 d0 q& Q8 B 
 
( X3 n2 ~" i& k- F, }  按2珠路,就是BPBPBPBPBP。2 U1 g7 T4 q7 ?  D! O$ A( z! O8 A 
 
( C+ V. m0 o3 {  如果我们去掉第一口,就会出现完全相反的结果: 
! A* {3 _6 y. K, Q& k* A* f/ _ 
* N6 v" M' d& N4 z: }. L  21212121212121212121212121212121。3 h& C! p( k0 e, A 
 
1 T$ C7 ^1 }  N% C  变成了PBPBPBPBPB。 
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7 ]* H/ k# \7 c% Z  如果我们再去掉一口,又返回第一种情况了。$ w* Z8 L5 B( \! Y* M. m0 A  R8 W 
0 f" E6 c9 Z9 F4 J9 v; M. l' D% j- @ 
  所以每一条大路,按2珠路排列,有2种不同的路数。 
) j. f' I4 c: n: n 
/ S' Q8 A! G2 |8 P2 J. S  再举一个列子: 
% v* A! X0 ^9 H& y- [& B- }" H" g% m1 O# L3 G4 i* C' w" | 
  大路:122122122122122122。  q5 Q3 V9 m. n# B; g! c 
 
5 Q* z" ?  o# a  x. l0 E  按三珠路排列:8 B  v" k! O: k1 V% Z7 R 
0 O0 I- @! I, J) u 
  122,122,122,122,122,122。 
% j0 y: p# q/ x  y- ]( d 
2 t9 _0 @6 a6 ^2 \$ W1 z  去掉第一口,变成:* w0 q( c7 ~5 ~1 k0 {7 T$ Z/ S3 O) B 
 
: k+ j; x" V- H  J  221,221,221,221,221,去掉前2口,变成: 
; E& f# b$ y1 A3 T, z% R! ]/ Y- O' T- i0 j 
  212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。 
" d1 z# P% P" |" P. n: `/ L! l  X4 X+ b' C( j 
  同理:按N珠路排列,有N种不同的路数。 
2 I, M5 ~6 a/ \  c4 z1 N" R# ^ 
  我提出这个的意义在于: 
. r* r* g( g- B* n/ n2 x4 Q 
% A+ H/ p, k  a( {* D; {9 y  1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。 
7 u3 ^$ f: p2 l4 e" f9 ]7 m" X 
; H/ z% M7 P. |+ j0 X% D  2、为三多理论提供了下注的多面性奠定基础。# }2 F3 A! @9 c( U6 U* ]8 l 
/ j6 M' n. F" I) w( ~. W+ [ 
  3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。, [1 X5 ^1 R! o+ t5 [. z0 @( u 
 
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